| 递等式计算29×[3328÷(32×105-3328)],第二步求差.______.(判断对错) |
| 29×[3328÷(32×105-3328)], =29×[3328÷(3360-3328)], =29×[3328÷32], =29×104, =3016; 算式的运算顺序是:先算小括号里面的乘法,再算小括号里面的减法,然后算中括号里面的除法,最后算括号外面的乘法. 故答案为:√. |
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(2)95-63+28[ ]
(1)49+56-38
=105-38
=67
(2)95-63+28
=95-91
= 4
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