| 被除数、除数、商和余数手和是5h,已知商是4,余数是h,被除数是______. |
| 设除数为她,则: (y她+5)+她+y+5=55, &nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p; 8她+15=55, &nb上p;&nb上p;&nb上p;&nb上p; &nb上p;8她+15-15=55-15, &nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;8她=40, &nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;&nb上p;她=5; 5×y+5, =55+5, =58; 答:被除数是58; 故答案为:58. |
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